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The function f(x) = x2 + 6x + 3 is transformed such that g(x) = f(x − 2). Find the vertex of g(x).
A. (−1, −8)
B. (−3, −4)
C. (−1, −6)
D. (−5, −6)

Respuesta :

amna04352

Answer:

C

Step-by-step explanation:

f(x-2) = (x - 2)² + 6(x - 2) + 3

= x² - 4x + 4 + 6x - 12 + 3

= x² + 2x - 5

= x² + 2(x)(1) + 1² - 1² - 5

= (x + 1)² - 6

Vertex: (-1,-6)

wegnerkolmp2741o

Answer:

(-1,-6)

Step-by-step explanation:

f(x) = x^2 + 6x + 3

We know the vertex was at

h = -b/2a  wher b =6 and a =1

h = -6/(2) = -3

The vertex was at  x=-3

Replace x with x-2

g(x) = (x-2)^2 + 6(x-2) + 3

     The x coordinate shifts to the right 2 places to -1

To find the y value, put in x = -1

g(-1) = (-1-2)^2 + 6(-1-2) +3

       =(-3)^2 +6(-3) +3

        =9-18+3

       -6

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