can someone help me figure out x?

Given:
Given that ABC is a right angled triangle.
The length of AB is 29 units.
Length of BC is 9 units.
The measure of ∠A is x.
We need to determine the value of x.
Value of x:
The value of x can be determined by using the trigonometric ratios.
Thus, we have;
[tex]sin \ A=\frac{BC}{AB}[/tex]
Substituting the values, we get;
[tex]sin \ x=\frac{9}{29}[/tex]
Simplifying, we get;
[tex]sin \ x=0.3103[/tex]
Taking [tex]sin^{-1}[/tex] on both sides, we get;
[tex]x=sin^{-1}(0.3103)[/tex]
[tex]x=18.08[/tex]
Thus, the value of x is 18.08
Hence, the measure of ∠A is 18.08°