Answer:
8
Step-by-step explanation:
Using the rule of exponents
[tex]\frac{a^{m} }{a^{n} }[/tex] = [tex]a^{(m-n)}[/tex] for m > n
[tex]\frac{a^{m} }{a^{n} }[/tex] = [tex]\frac{1}{a^{(n-m)} }[/tex] for n > m
Simplifying the expression inside the parenthesis
[tex]\frac{6^73^3}{6^63^4}[/tex]
= [tex]\frac{6^{(7-6)} }{3^{(4-3)} }[/tex]
= [tex]\frac{6}{3}[/tex] = 2
Thus
[tex](2)^{3}[/tex] = 8
