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find the surface area of a regular hexagonal pyramid with a base edge of 16 m with a and a slant height of 15 m

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Answer:

1385.28 m²

Step-by-step explanation:

apothem = √16² - 8² = √256 - 64 = √192 = 13.86

Base area = 3 x 16 x 13.86 = 665.28

6 side area = 3 x 16 x 15 = 720

surface area = 665.28 + 720 =1385.28

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