The probability that he will pull out a nickel, then a quarter, then a nickel is [tex]\frac{1}{33}[/tex]
Explanation:
Given:
Number of dimes = 3
Number of Quarters = 2
Number of pennies = 2
Number of Nickles = 5
Total coins = 3 + 2 + 2 + 5
= 12
Probability that Armando will pull out Nickel first = [tex]\frac{5}{12}[/tex]
After taking out Nickel, the total number of coins in the pocket will be 11
So,
Probability that he will pull a quarter = [tex]\frac{2}{11}[/tex]
Total coins remaining = 11 - 1 = 10
Total Nickel remaining = 5 - 1 = 4
Probability that he will take our Nickel = [tex]\frac{4}{10} = \frac{2}{5}[/tex]
Total probability = [tex]\frac{5}{12} X \frac{2}{11} X\frac{4}{10}[/tex]
= [tex]\frac{1}{33}[/tex]