Answer:
The answer to your question is T2 = 5755.8 °K
Explanation:
Data
temperature 1 = 89 °C
Volume 1 = 0.67L
temperature 2 = ?
Volume 2 = 15.9 L
Process
Use Charles' law to solve this problem
V1/T1 = V2/T2
-Solve for T2
T2 = V2T1/V1
-Convert temperature to °K
temperature 1 = 89 + 273 = 362°K
-Substitution
T2 = (15.9 x 362) / 0.67
-Simplification
T2 = 5755.8 / 0.67
-Result
T2 = 5755.8 °K
