9400 dollars is placed in an account with an annual interest rate of 6.25%. To the nearest tenth of a year, how long will it take for the account value to reach 47100 dollars?

Respuesta :

Answer:

[tex]t=64.2\ years[/tex]

Step-by-step explanation:

we know that

The simple interest formula is equal to

[tex]A=P(1+rt)[/tex]

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

[tex]t=?\ years\\ P=\$9,400\\ A=\$47,100\\r=6.25\%=6.25/100=0.0625[/tex]

substitute in the formula above

[tex]47,100=9,400(1+0.0625t)[/tex]

solve for t

[tex]t=[(47,100/9,400)-1]\0.0625[/tex]

[tex]t=64.2\ years[/tex]

Answer: the answer is 26.6

Step-by-step explanation: