Answer:
A: The space inside dollhouse 1 can be found using the equation V = 6 (6) (5) + one-half (6) (6) (4).
D: The space inside dollhouse 2 can be found using the equation V = 6 (6) (5) + one-third (6) (6) (4).
E: The space inside dollhouse 1 is 24 inches cubed greater than the space inside dollhouse 2.
Step-by-step explanation:
ANSWERS ARE A, D, E !!
i just took it on EDGE 2020 - hope it helps :)
The difference between the space of Dollhouse 1 and Dollhouse 2 will be 24 in³. Then the correct options are A, D, and E.
It deals with the size of geometry, region, and density of the different forms both 2D and 3D.
Mr. Petrov was trying to choose between two different plans for dollhouses for his daughter.
Both dollhouses have a rectangular prism base with a length of 6 inches, a width of 6 inches, and a height of 5 inches.
Dollhouse 1 has a triangular prism top.
The triangular base has a base of 6 inches and a height of 4 inches.
The prism has a height of 6 inches.
Dollhouse 2 has a square pyramid top with a base of 6 inches by 6 inches and a height of 4 inches.
Then the space inside the Dollhouse 1 (SD₁) will be
[tex]\rm SD_1 = 6 \times 6\times 5 + \dfrac{1}{2}\times 6\times 4\times 6\\\\SD_1 = 252 \ in^3[/tex]
Then the space inside the Dollhouse 1 (SD₂) will be
[tex]\rm SD_2 = 6 \times 6\times 5 + \dfrac{1}{3}\times 6\times 6\times 4\\\\SD_2 = 228\ in^3[/tex]
Then the difference in the space of Dollhouse 1 and Dollhouse 2 will be
→ SD₁ - SD₂ = 252 - 228 = 24 in³
More about the geometry link is given below.
https://brainly.com/question/7558603
