The following colored pens were placed in a backpack.
• 3 red
. 3 black
• 2 blue
. ? purple
How many purple pens need to be in the backpack in
order for the probability of pulling out a red pen, no
replacing it, then pulling out a purple pen to be 1/15?​

Respuesta :

The number of purple pen is 2

Explanation:

Number of red pens = 3

Number of black pens = 3

Number of blue pens = 2

Number of purple pens = ?

Probability = [tex]\frac{1}{15}[/tex]

Total number of pens = 3 + 3 + 2 + x

                                  = 8 + x

The probability of pulling out a red pen = [tex]\frac{3}{8+x}[/tex]

Total number of pens become = 8 + x - 1

                                               = 7 + x

Probability of pulling out a purple pen = [tex]\frac{x}{7+x}[/tex]

According to the question:

[tex]\frac{3}{8+x} X\frac{x}{7+x} = \frac{1}{15}[/tex]

Solving the equation:

[tex]\frac{3x}{8(7+x) + x (7+x)} = \frac{1}{15} \\\\\frac{3x}{56 + 8x + 7x + x^2} = \frac{1}{15} \\[/tex]

[tex]\frac{3x}{56+ 15x + x^2} = \frac{1}{15} \\\\45x = 56 + 15x + x^2\\\\x^2 - 30x + 56 = 0\\\\x = 28, 2[/tex]

If x = 2 then,

[tex]\frac{3}{8 +2} X \frac{2}{7+2} = \frac{3}{10} X \frac{2}{9} = \frac{1}{15}[/tex]

Therefore, the number of purple pen is 2