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The acceleration of an object is given by a(t)=cos(πt). The velocity of the object at time t=0 is 1/(2π). Which expression can be used to find the total distance traveled in the first 11/6 seconds?

The acceleration of an object is given by atcosπt The velocity of the object at time t0 is 12π Which expression can be used to find the total distance traveled class=

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amna04352

Answer:

D

Step-by-step explanation:

v(t) = (1/pi) × sin(pi × t) + c

At t = 0, v = 1/2pi

1/2pi = 0 + c

v(t) = (1/pi)sin(pi×t) + 1/(2pi)

Takes a turn when v = 0

0 = (1/pi)sin(pi×t) - 1/(2pi)

sin(pi × t) = -½

pi × t = 7pi/6

t = 7/6

For t = 0 to t = 7/6,

V(t) > 0

So s(t) > 0

For t = 7/6 to t = 11/6,

Displacement is negative, so put a mod

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