Answer:
The heat required is 1262.91 joules or 1.26 kilojoules.
Explanation:
The quantity of heat (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Since,
Q = ?
Mass of aluminum sample = 33.0g
C = 0.89 J/g℃
Φ = (Final temperature - Initial temperature)
= 68°C - 25°C = 43°C
Then, Q = MCΦ
Q = 33.0g x 0.89 J/g℃ x 43°C
Q = 1262.91 J
Since the heat in joules is 1262.91, obtain heat in kilojoules.
If 1000 joules = 1 kilojoules
1262.91 joules = Z
To get Z, cross multiply
Z x 1000 = 1262.91 x 1
1000Z = 1262.91
Z = 1262.91 / 1000
Z = 1.26291 kilojoules (when placed as 3 significant figures, Z is 1.26 kilojoules)
Thus, the heat required is 1262.91 joules or 1.26 kilojoules.