If the triangle has the angle of 90°, 89° and 1° then 1 side length can be 3 in but all the side lengths cannot be 3 in.
Explanation:
The sum of all the angles of a triangle = 180°
So, if 1 angle is 90° and the 2nd angle is 89°, then the third angle will be 1°
and length of 1 side = 3 in
a = 3 in
Using the Sine rule,
[tex]\frac{sin A}{a}= \frac{sin B}{b} = \frac{sin C}{c}[/tex]
On substituting the value:
[tex]\frac{sin 90^o}{3} = \frac{sin 89^o}{b} = \frac{sin 1^o}{c} \\\\\frac{1}{3} =\frac{0.99}{b}= \frac{0.017}{c} \\\\b = 3 X 0.99 = 2.97 in\\\\c = 3 X 0.017 = 0.051 in[/tex]
Therefore, if the triangle has the angle of 90°, 89° and 1° then 1 side length can be 3 in and the triangle will be very acute but all the side lengths cannot be 3 in.
