Explanation:
In order to solve this problem, let's choose a trapezoid which is a quadrilateral where at least one pair of opposite sides are parallel. The area (A) of this shape is given by:
[tex]A=\frac{(b_{1}+b_{2})h}{2} \\ \\ \\ Where: \\ \\ b_{1},b_{2}:Are \ parallel \ bases \\ \\ h:height[/tex]
Since we must use the digits 0-9 at most one time, let's choose digits 2, 4 and 6 this way:
[tex]b_{1}=2 \\ \\ b_{2}=6 \\ \\ h=4[/tex]
Then, the area is:
[tex]A=\frac{(2+6)4}{2} \\ \\ A=\frac{32}{2} \\ \\ A=16 \ sq \ units[/tex]
So our quadrilateral satisfies the given statement.
