Respuesta :
Answer:
Step-by-step explanation:
y= a*b x (a is initial value b = growth rate) y= 8000(-1)^1 x= 1.018^1 x 1.8
x = 0.1527 = time x 12.
f(x)=x. f ( x ) = x . = 0.1527 x 12
or we can square so that x^2 = 1.8 and x = 1.34164 note this can only be used for the first 5 decimal place.
This shows the exponential growth we expand and introduce y = 8000(-1)^12 to find one year.
One year y-1^12 this represents 144 the 1.8% of the y = 144 the starting point of 1/12 on axis.
f(x)=2x. f ( x ) = 2x add y (1)^1 would show year 2 at the same rate,
Using an exponential function, it is found that the monthly increase rate of 0.15% and the exponential function for the population after t months is given by:
- [tex]A(t) = 8000(1.0015)^t[/tex]
Exponential function:
- A increasing exponential function is modeled by:
[tex]A(t) = A(0)(1 - r)^t[/tex]
In which:
- A(0) is the initial value.
- r is the rate of increase, as a decimal.
In this problem:
- The initial population is of 8,000, hence [tex]A(0) = 8000[/tex].
- It increases at a rate of 1.8% per year, hence, per month, the rate is [tex]r = \frac{0.018}{12} = 0.0015[/tex].
Hence, considering the monthly increase rate of 0.15%, the exponential function for the population after t months is given by:
- [tex]A(t) = 8000(1.0015)^t[/tex]
To learn more about exponential functions, you can take a look at https://brainly.com/question/25537936
