Answer:
correct answer: Vmax = 36 m/s
Explanation:
Given:
m = 1,500 kg the mass of the roller coaster
H = 65 m the height of the hilltop
Vmax = ? the maximum speed which roller coaster will have at the bottom of the hill
We will solve this problem using energy conservation laws:
At the top of the hill, the total roller coaster energy is equal to the maximum potential energy while the kinetic energy is zero:
Etotal = Epmax and Ek = 0 J
The formula for calculating potential energy is:
Ep = m g H we will take g = 10 m/s²
Epmax = m g H
At the bottom of the hill, the total roller coaster energy is equal to the maximum kinetic energy while the potential energy is zero:
Etotal = Ekmax and Ep = 0 J
The formula for calculating kinetic energy is:
Ek = m V² / 2
Ekmax = Etotal = Epmax
Ekmax = m Vmax² / 2 = m g H
m Vmax² / 2 = m g H when we divide both sides by mass m we get:
Vmax² / 2 = g · H ⇒ Vmax² = 2 · g · H
Vmax² = 2 · 10 · 65 = 1300
Vmax = √1300 = 36 m/s
Vmax = 36 m/s
God is with you!!!
