PLEASE HELPLPPP!!!!!

A car driving at an initial velocity of 7.5 m/s accelerates at a rate of 2.0 m/s2 for 2.5
seconds. What distance does the car travel during this time period?
A.14 m
B.21 m
C.25 m
D.31 m

Respuesta :

Answer:

Correct answer:  C.  D = 25 m

Explanation:

Given:

V₀ = 7.5 m/s  Initial velocity

a = 2 m/s²   acceleration

t = 2.5 seconds  the time interval for which the distance traveled is required

According to the data provided, we have seen that the subject is a uniformly accelerated motion to which the formula applies:

D = V₀ · t + (a · t₂²)/2

D = 7.5 · 2.5 + (2 · 2.5²) / 2 = 18.75 + 6.25 = 25 m

D = 25 m

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