This problem is providing both the mass and temperature change of water when the energy in a serving food is used to heat it up. It asks for the calories, and therefore the answer turns out to be 450,000 cal.
Calorimetry.
In chemistry, calorimetry problems involving heat, specific heat, mass and temperature can be solved with the general heat equation relating these four:
[tex]Q=mC\Delta T[/tex]
Thus, given the mass of water, its specific heat as 1 cal/(g°C) and the temperature change, the heat, in calories, supplied by this serving food turns out to be:
[tex]Q=450,000g*1\frac{cal}{g\°C}*1\°C\\ \\Q=450,000cal=450kcal[/tex]
Learn more about calorimetry: brainly.com/question/1407669
