Answer:
20 feet
Step-by-step explanation:
The value of y is zero where x=2 and x=22. The distance between those points is 22 -2 = 20 feet.
The ball lands 20 feet from where it leaves the ground.
The ball lands 20 feet from where it leaves the ground.
Given that,
The path of a ball kicked from the ground can be modeled by the equation,
[tex]\rm y=\dfrac{-1}{4}(x-2)(x-22)[/tex]
Where x and y are measured in feet.
The x-axis represents the ground.
We have to determine,
How far does the ball land from where it is kicked?
According to the question,
The distance does the ball lands from where it is kicked is determined when y becomes 0. when it started with the change in y is 0.
[tex]\rm y=\dfrac{-1}{4}(x-2)(x-22)\\\\\rm\dfrac{-1}{4}(x-2)(x-22)=0[/tex]
[tex]\rm (x-2)(x-22)=0\\\\x - 2= 0 \ x = 2\\\\x -22 =0 \ x = 22[/tex]
The difference between the ball lends from where it is kicked is,
= 22- 2 = 20 feet
Hence, The ball lands 20 feet from where it leaves the ground.
To know more about Parabolas click the link given below.
https://brainly.com/question/24717656
