[NEED THIS ANSWERED QUICKLY]
What is the surface area of the triangular prism?

Given:
The base of the triangle is b = 3 feet.
The height of the triangle is h = 4 feet.
The other side of the triangle is 5 feet.
The height of the triangular prism is 20 feet.
We need to determine the surface area of the triangular prism.
Surface area of the triangular prism:
The surface area of the triangular prism is given by the formula,
[tex]SA=bh+(s_1+s_2+s_3)H[/tex]
where b is the base of the triangle,
h is the height of the triangle,
s₁ , s₂ and s₃ are the sides of the triangle and
H is the height of the triangular prism.
Substituting the values, we get;
[tex]SA=(3)(4)+(3+4+5)(20)[/tex]
[tex]SA=12+(12)(20)[/tex]
[tex]SA=12+240[/tex]
[tex]SA=252 \ ft^2[/tex]
Thus, the surface area of the triangular prism is 252 ft²