Answer:
The answer to your question is [tex]\frac{x^{2}}{60^{2}} - \frac{y^{2}}{11^{2}} = 1[/tex]
Step-by-step explanation:
Data
From the graph
Horizontal hyperbola
Center (0, 0)
a = 60 a is the distance from the Center to the Vertex
b = 11 b is the distance from the Center to the endpoint of the conjugate
axis.
The Equation for a horizontal hyperbola
[tex]\frac{(x- h)^{2} }{a^{2}} - \frac{(y - k)^{2}}{b^{2}} = 1[/tex]
h = 0, k = 0
-Substitution
[tex]\frac{x^{2}}{60^{2}} - \frac{y^{2}}{11^{2}} = 1[/tex]
