Answer:[tex]2\sqrt{58}[/tex]
Step-by-step explanation:
the diagonal of a rectangle is the same as the hypotenuse of a right triangle. So we already have two sides of this right triangle the short side being 6 in and the long side being 14. We can use the pythagorean theorem to solve.
[tex]a^2+b^2=c^2\\14^2+6^2=232\\c^2=232\\c=2\sqrt{58}[/tex]
