Step-by-step explanation:
a) According to the least-squares regression line, the estimated height for a high school senior with a foot length of 20 cm is:
y = 2.599x + 105.08
y = 2.599(20) + 105.08
y = 157.06
The residual is 160 − 157.06 = 2.94
b) The differences between each data point and its corresponding estimate varies with a standard deviation of 5.9 cm.
c) Calculate the z-score:
z = (x − μ) / σ
z = (8 − 0) / 5.9
z = 1.36
Use a calculator or table to find the probability.
P(Z > 1.36) = 1 − 0.9131 = 0.0869
Therefore, approximately 8.69% of the residuals are larger than 8 cm.
d) Since the z-score is within ±2 standard deviations, it would not be surprising to randomly select a high school senior with a foot length of 20 cm and height of 165 cm.