Respuesta :
H₂SO₃ has the larger percent composition of sulfur when compared to H₂S₂O₈.
Explanation:
To find the largest percent of composition of sulfur, we have to divide the mass of sulfur divided by the total mass of the molecule multiplied by 100.
H₂SO₃
Mass of H = 1 × 2 = 2
Mass of S = 32×1 = 32
Mass of O = 16 × 3 = 48
Total mass of H₂SO₃ = 82 g
Total mass of H₂S₂O₈ = 2+ (2×32) + (8×16) = 194
Percent composition of S in H₂SO₃ = [tex]$\frac{32}{82}\times 100[/tex]
= 39%
Percent composition of S in H₂S₂O₈ = [tex]$\frac{64}{194}\times 100[/tex]
= 32.9 ≈ 33 %
H₂SO₃ has the larger percent composition of sulfur when compared to.
- Calculation of the larger percent:
Mass of H [tex]= 1 \times 2[/tex] = 2
Mass of S = [tex]32\times 1[/tex]= 32
Mass of O = [tex]16 \times 3[/tex] = 48
Total mass of [tex]H_2SO_3[/tex]= 82 g
Total mass of [tex]H_2S_2O_8[/tex] = [tex]2+ (2\times 32) + (8\times 16)[/tex]= 194
Now
Percent composition of S in [tex]H_2SO_3[/tex] [tex]= 32 \div 82 \times 100[/tex] = 39%
And, Percent composition of S in [tex]H_2S_2O_8[/tex] = [tex]64 \div 194 \times 100[/tex] = 33%
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