jandckarl
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What is the point-slope form of a line that has a slope of -4 and passes through point (-3, 1)?
O y-(-3)=-4(x-1)
O y-1 =-4[x-(-3)]
O-1-y,--4-3-x)
O 3-y, = -4(1-x)

Respuesta :

Edufirst

Answer:

Second choice:

       [tex]y-1=-4[x -(-3)][/tex]

Explanation:

The point-slope form of a line is:

       [tex]y-y_1=m(x-x_1)[/tex]

Where m is the slope and x₁, y₁ are the coordinates of any point that is on the line,

In this case, you are given:

  • m = -4
  • x₁ = -3
  • y₁ = 1

Substituting in the point-slope form you get:

       [tex]y-1=-4[x -(-3)][/tex]

Which is the second option.

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