Answer:
k = -1 and k = -2
Step-by-step explanation:
We can use the quadratic formula, which says that for the quadratic [tex]ax^2+bx+c=0[/tex], the solutions are: x = [tex]\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex] or [tex]\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex] .
Here, a = 4, b = 12, and c = 8, so: x = [tex]\frac{-12+\sqrt{12^2-4*4*8} }{2*4}[/tex] or [tex]\frac{-12-\sqrt{12^2-4*4*8} }{2*4}[/tex].
Simplifying, we get k = -1 or k = -2.
Thus, k = -1 and -2.
Hope this helps!
