Use slope formula,m = StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction, to find the slope of a line that passes through the points (–3, 8) and (4, –6).

m =
Use slope-intercept form, y = mx + b, to find the y-intercept (b) of the line.

b =
What is the new equation written in slope-intercept form, y = mx + b?


Respuesta :

Answer:

m = -2

b = 2

y= -2x+2

Step-by-step explanation:

First, slope is change in y over change in x, or rise over run. Plugging these points in, (y2-y1)/(x2-x1)=(-6-8)/(4--3), or -14/7, simplifying, the slope= -2.

Now, we have y=2x+b. Using the point (-3,8), 8=-2*-3+b, or 8=6+b, subtracting 6, 2=b.

Using slope intercept form, y=mx+b, or y=-2x+2.

fichoh

The slope, intercept and linear equation of the relation given are :

  • Slope = - 2
  • Intercept = 2
  • Linear equation : y = - 2x + 2

Given the points :

  • (-3, 8) ; (4, - 6)

The slope formula :

  • (y2 - y1) ÷ (x2 - x1)

  • y2 = - 6 ; y1 = 8 ; x2 = 4 ; x1 = - 3

  • (-6 - 8) ÷ (4 - (-3)) = (-14) ÷ 7 = - 2

  • The slope, m = - 2

Using the linear relation :

  • y = mx + b
  • Taking the point (-3, 8)
  • 8 = - 2(-3) + b
  • 8 = 6 + b
  • b = 8 - 6
  • b = 2

Therefore, the slope, = - 2 and intercept = 2

The new equation written in the form y = mx + b will be ;

  • y = - 2x + 2

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