You pick a card from a standard deck, look at it, then pick a second card. Since a standard deck of 52 cards has 13 hearts and 13 diamonds, is the probability of drawing a heart and then a diamond 13 52 · 13 52 ?
A) Yes; because the two events are independent.
B) No; because the two events are not independent.
C) Yes; because the two events are disjoint -- no card is both hearts and diamonds.
D) No; because the two events are not disjoint -- a card can be both hearts and diamonds.

((Went back and it gave me the answer. B) No; because the two events are not independent. Since the first card is not being replaced, the two events are not independent -- there are only 51 cards to draw from for the second card.))

The probability of drawing a heart and then a diamond is [tex]\dfrac{13}{52}\times\dfrac{13}{51}[/tex]. The correct option is B) No; because the two events are not independent.

Given information:

Two cards are drawn from the deck of 52 cards one by one.

There are 13 heart cards and 13 diamond cards.

When we draw first card, the probability of drawing the heart will be,

[tex]P(h)=\dfrac{13}{52}=\dfrac{1}{4}[/tex]

Now, we have 51 cards left. So, in the 2nd draw, the probability of getting a diamond card will be,

[tex]P(d)=\dfrac{13}{51}[/tex]

So, the overall probability of the event will be,

[tex]P=P(h)\times P(d)\\P=\dfrac{13}{52}\times\dfrac{13}{51}[/tex]

Therefore, the probability of drawing a heart and then a diamond is [tex]\dfrac{13}{52}\times\dfrac{13}{51}[/tex]. The correct option is B) No; because the two events are not independent.

For more details, refer to the link:

https://brainly.com/question/795909