Special right triangles
Help me find s

Answer:
s = 3[tex]\sqrt{3}[/tex]
Step-by-step explanation:
Using the cosine ratio in the right triangle and the exact value
cos30° = [tex]\frac{\sqrt{3} }{2}[/tex]
cos30° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{s}{6}[/tex] = [tex]\frac{\sqrt{3} }{2}[/tex] ( cross- multiply )
2s = 6[tex]\sqrt{3}[/tex] ( divide both sides by 2 )
s = 3[tex]\sqrt{3}[/tex]