Answer : The volume of gas sample will be, 9.93 L
Explanation :
Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles of gas.
Mathematically,
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1\text{ and }T_1[/tex] are the initial volume and temperature of the gas.
[tex]V_2\text{ and }T_2[/tex] are the final volume and temperature of the gas.
We are given:
[tex]V_1=11.3L\\T_1=32^oC=(32+273)K=305K\\V_2=?\\T_2=-5^oC=(-5+273)K=268K[/tex]
Now put all the given values in above equation, we get:
[tex]\frac{11.3L}{305K}=\frac{V_2}{268K}\\\\V_2=9.93L[/tex]
Therefore, the volume of gas sample will be, 9.93 L