Answer:
The area of the trapezoid is 57.5 square inches
Step-by-step explanation:
we know that
The trapezoid QRST can be divided into a rectangle QRDT and an isosceles right triangle RSD
see the attached figure to better understand the problem
step 1
The area of rectangle is given by the formula
[tex]A=((QR)(RD)[/tex]
we have
[tex]RD=5\ in[/tex] ----> altitude
[tex]QR=9\ in[/tex]
substitute
[tex]A=((9)(5)=45\ in^2[/tex]
step 2
Find the area of the isosceles right triangle
The area of triangle is given by the formula
[tex]A=\frac{1}{2}(RD)(DS)[/tex]
we have
[tex]RD=DS=5\ in[/tex] ---> because is an isosceles triangle
substitute
[tex]A=\frac{1}{2}(5)(5)=12.5\ in^2[/tex]
step 3
Adds the areas
[tex]A=45+12.5=57.5\ in^2[/tex]
Answer:
57.5
Step-by-step explanation:
First you have to solve the rectangle with the formula A=B time height:
9 times 5 is 45, the area of the rectangle is 45
Next, solve the area of the triangle. The triangle is isosceles so the height and base are the same. The formula is base times height /2
Area=5 times 5 = 25. 25 divided by 2 is 12.5.
Now add the areas together (45+12.5). Your answer will be 57.5.
