Answer:
B. No
[tex]Cos \ \theta\neq Cos (90-\theta)\textdegree[/tex]
Step-by-step explanation:
-A right angle triangle has two complimentary acute angles and one right angle.
-[tex]\theta[/tex] is usually one of the acute angles and is equivalent to 90º minus it's complimentary acute angle.
-Complimentary angles add up to 90º.
#For complimentary angles:
[tex]Sin \ \theta=Cos \ (90-\theta)\textdegree\\\\Cos \ \theta=Sin(90-\theta)\textdegree\\\\\therefore Cos \ \theta\neq Cos (90-\theta)\textdegree[/tex]
The two acute angles cannot have the same Cosine value.
Hence, she's not correct.
