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WILL GIVE BRAINLIEST
The length of a rectangular frame is represented by the expression 2x + 8, and the width of the rectangular frame is represented by the expression 2x + 6. Write an equation to solve for the width of a rectangular frame that has a total area of 160 square inches.
4x2 + 32x + 48 = 0
4x2 + 28x − 112 = 0
2x2 + 32x − 112 = 0
x2 + 12x + 48 = 0

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mobilegamingexpert

Answer:

B. 4x^2=28x-112=0.

Step-by-step explanation:

Using area=length*width, 160=(2x+8)(2x+6).

Expanding, (2x+8)(2x+6)=4x^2+16x+12x+48.

Setting this equal to 160, 160=4x^2+28x+48, or 4x^2+28x-112=0.
the answer is B. 4x2+32x+48=0

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