The first of the sequence is -6.25.
The second term of the sequence is -7.81.
The third term of the sequence is -9.81.
The fourth term of the sequence is -12.20.
The fifth term of the sequence is -15.25.
The sixth term of the sequence is -19.07.
We have to determine, the six terms of a finite sequence and graph these terms.
According to the question,
The first term of the sequence = -6.25
And the common ratio is = 1.25
The six terms of finite sequence would be as per the following equation is determined by the formula,
[tex]\rm f(x)= a_1 \times r^ {(n-1)}[/tex]
1. The first of the sequence is -6.25.
2. The second term of the sequence is,
[tex]\rm a_2=(-6.25) \times (1.25)^ {(2-1)}\\\\a_2 = (-6.25) \times 1.25\\\\a_2 = -7.81[/tex]
The second term of the sequence is -7.81.
3. The third term of the sequence is,
[tex]\rm a_3=(-6.25) \times (1.25)^ {(3-1)}\\\\a_3 = (-6.25) \times (1.25)^2\\\\ a_3 = (-6.25) \times 1.56\\\\a_3 = -9.81[/tex]
The third term of the sequence is -9.81.
4. The fourth term of the sequence is,
[tex]\rm a_4=(-6.25) \times (1.25)^ {(4-1)}\\\\a_4= (-6.25) \times (1.25)^3\\\\ a_4 = (-6.25) \times 1.95\\\\a_4 = -12.20[/tex]
The fourth term of the sequence is -12.20.
5. The fifth term of the sequence is,
[tex]\rm a_5=(-6.25) \times (1.25)^ {(5-1)}\\\\a_5= (-6.25) \times (1.25)^4\\\\ a_5 = (-6.25) \times 2.44\\\\a_5= -15.25[/tex]
The fifth term of the sequence is -15.25.
6. The sixth term of the sequence is,
[tex]\rm a_6=(-6.25) \times (1.25)^ {(6-1)}\\\\a_6= (-6.25) \times (1.25)^5\\\\ a_6 = (-6.25) \times 3.05\\\\a_6= -19.07[/tex]
The sixth term of the sequence is -19.07.
For more details refer to the link given below.
https://brainly.com/question/12895249
