Answer:
[tex]\frac{15}{56}[/tex]
Step-by-step explanation:
This is a probability event that expresses the likelihood of an event to occur.
Number of paper clips in sack = 3
Number of erasers in sack = 5
Problem: Probability that one will draw a paper clip and then an eraser?
These are two mutually exclusive events.
Total number of paper in sack = 3 + 5 = 8
Pr(drawing paper clip) = [tex]\frac{3}{8}[/tex]
without replacement suggests that the total number of paper in sack will reduce by 1 to 7;
Pr(drawing eraser) = [tex]\frac{5}{7}[/tex]
So:
Pr(paper clip and eraser ) = [tex]\frac{3}{8} x \frac{5}{7}[/tex] = [tex]\frac{15}{56}[/tex]
