Given:
The given equation of the circle is [tex]x^{2} +(y-12)^2=5[/tex]
We need to determine the center and radius of the circle.
Radius:
Let us determine the radius of the circle using the general equation for circle [tex](x-h)^2+(y-k)^2=r^2[/tex]
Comparing the two equations, we have;
[tex]r^2=5[/tex]
Taking square root on both sides, we get;
[tex]r=\sqrt{5}[/tex]
[tex]r=2.2[/tex]
Thus, the radius of the circle is 2.2 units.
Center(h,k):
The center of the circle can be determined using the general equation of the circle [tex](x-h)^2+(y-k)^2=r^2[/tex]
Comparing the general equation with the equation of the circle, we have;
[tex](h,k)=(0,12)[/tex]
Thus, the center of the circle is (0,12)
