Answer:
It is elastic potential energy
Explanation:
Elastic potential energy is stored energy that results from applying a force to deform an elastic object. The energy is stored until the force is removed and the elastic object returns to its original shape, doing work in the process. Deformation may involve compressing, stretching, or twisting the object. Many objects are specifically designed to store elastic potential energy, for example:
The spring of a winding watch.
Answer:
Perubahan energi potensial pegas adalah 17.1675 J
Explanation:
Untuk menyelesaikan pertanyaan, kami mencatat bahwa energi potensial elastis diberikan sebagai;
Energi potensial elastis= [tex]E_p=\frac{1}{2} \times k \times x^{2}[/tex]
Dimana:
k = Konstanta pegas
x = perpanjangan musim semi = 7 cm = 0.07 m
Paksa di musim semi = -kx
Di mana, pegas adalah satu-satunya objek yang berkontribusi pada gaya yang kita miliki
Memaksa= m×g = 5 × 9.81 = 49.05 N
Karena itu, k = 49.05/0.07 = 700.714 N/m
Oleh karena itu, perubahan energi potensial elastis adalah
[tex]E_{p1}=\frac{1}{2} \times k \times x_1^{2}\\E_{p2}=\frac{1}{2} \times k \times x_2^{2}\\\Delta E_p = E_{p2} -E_{p1} = \frac{1}{2} \times k \times x_2^{2} - \frac{1}{2} \times k \times x_1^{2} = \frac{1}{2} \times k \times (x_2^{2} - x_1^{2})[/tex]
Kami memiliki, x₁ = 0 m karena pegas diasumsikan awalnya tidak diregangkan
Karena itu,
[tex]\Delta E_{p}=\frac{1}{2} \times k \times x_2^{2}[/tex]
[tex]\Delta E_{p}=\frac{1}{2} \times 700.714 \times 0.07^{2} = 17.1675 J[/tex] and
Perubahan energi potensial pegas = 17.1675 J
