anna00271336
contestada

80.0 grams of NaOH is dissolved in water to make a 6.00 L
solution. What is the molarity of the solution? (Molar mass of
NaOH = 40.0 g/mol) _M

Respuesta :

The answer for the following problem is mentioned below.

  • Therefore the molarity of the solution is 3 × [tex]10^{-4}[/tex] M.

Explanation:

Given:

mass of sodium hydroxide solution (NaOH) = 80.0 grams

Gram molecular mass of sodium hydroxide solution (NaOH) = 40.0 gram/mole

volume of the solution (v) = 6.00 L = 6000 ml

To find:

molarity of the solution (m)

We know,

m = [tex]\frac{n}{v}[/tex]

where,

m represents the molarity of the solution

n represents the no of moles

v represents the volume of the solution

we also know;

n = [tex]\frac{m}{M}[/tex]

where,

m represents the mass of the sodium hydroxide

M represents the Gram molar mass of the solution

So,

n = [tex]\frac{80}{40}[/tex]

n = 2

So,

m =  [tex]\frac{2}{6000}[/tex]

m = 3 × [tex]10^{-4}[/tex] M

Therefore the molarity of the solution is 3 × [tex]10^{-4}[/tex] M.

samueladesida43

The molarity of 6.00 liters of an aqueous solution that contains 80g of sodium hydroxide is 0.33M.

HOW TO CALCULATE MOLARITY:

  • The molarity of a solution can be calculated by dividing the number of moles by its volume. That is;

Molarity = no. of moles ÷ volume

  • According to this question, 6.0 liters of an aqueous solution that contains 80/40 = 2 mol of sodium hydroxide. The molarity is calculated as follows:

Molarity = 2mol ÷ 6L

Molarity = 0.33M

Therefore, the molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of sodium hydroxide is 0.33M.

Learn more about molarity at: brainly.com/question/2817451

Otras preguntas