Answer:
[tex]Cos \angle B=\frac{63}{13}[/tex]
Step-by-step explanation:
-Given that ΔBCD is a right triangle with ∠D=90° as in the attached figure.
-The ratio of Cos of ∠B can be obtained using the right triangle identities:
[tex]Cos \ \theta=\frac{Adjacent}{Hypotenuse}\\\\Cos \ B=\frac{63}{16}[/tex]
Hence, the cosine of ∠B can be represented by the ratios [tex]Cos \angle B=\frac{63}{13}[/tex]
