The surface areas of two similar solids are 169 m2 and 81 m2. The volume of the larger solid is 124.92 m3. Which proportion correctly shows how to solve for the volume of the smaller solid, x?

A:13/9 = 124.92/x

B:169/81 = 124.92/x

C:13^3/9^3 = 124.92/x

D:169^3/81^3 = 124.92/x