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Which of the following shows the true solution to the logarithmic equation solved below?
log2 (x)+log2(x+ 7) = 3
log2[x(x+7)] = 3
*(X+ 7)- 23
x2 + 7x-8-0
(x+3)(x-1)=0
X=-8,1
0
0
X=-8
X-1
x= 1 and x=-8
X= 1 and X= 8

Respuesta :

Answer:

The answer is x=1

x = -8 and x = 1 are the true solutions of the given logarithmic equation.

What is logarithmic equation?

A logarithmic equation is an equation that involves the logarithm of an expression containing a variable.

[tex]log_{2}(x)+log_{2}(x+7) = 3\\\\log_{2}(x)(x+7)=3\\\\log_{2}(x^{2} +7x) = 3\\\\x^{2} +7x = 2^{3} = 8\\ \\x^{2} +7x -8 =0\\\\x^{2} +8x-x-8=0\\\\(x+8)(x-1) =0\\\\x = -8\ and\ x = 1[/tex]

Learn more about logarithmic equation here

https://brainly.com/question/3181916

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