Pressure of the nitrogen gas is 2290 kPa.
Explanation:
Using the ideal gas equation, we can find the pressure of the gas using the equation as,
PV = nRT
Where P is the pressure = ?
V is the volume = 3,456 ml = 3.456 L
n is the number of moles = [tex]$\frac{given mass}{molar mass}[/tex] = [tex]$\frac{45.2g }{14 g/mol}[/tex] = 3.2 mol
R is the gas constant = 0.08205 L atm K⁻¹ mol⁻¹
T is the temperature = 25 + 273 = 298 K
Now, rewriting the equation, we will get,
P = [tex]$\frac{nRT}{V}[/tex]
= [tex]$\frac{3.2 \times 0.08205\times 298 K }{3.456 L}[/tex]
= 22.6 atm
Now Pressure in 22.6 atm is converted as 2290 kPa.
