Respuesta :
1. [tex]H_{2}[/tex]S[tex]O_{4}[/tex] + Sr(OH)[tex]_{2}[/tex] ⇒ SrSO4 + 2 H2O is the balanced reaction.
2. 0.034 liters of KI will be required completely react with 2.43 g of Cu(NO3)2.
3. 0.55 liters is the volume in L of a 0.724 M Nal solution contains0.405 mol of NaI.
4. 33.3 ml many mL of 0.300 M NaF would be required to make a 0.0400 M solution of NaF when diluted to 250.0 mL with water
Explanation:
Balance chemical reaction of neutralization:
1. [tex]H_{2}[/tex]S[tex]O_{4}[/tex] + Sr(OH)[tex]_{2}[/tex] ⇒ SrSO4 + 2 H2O
2. Data given:
balance chemical reaction:
2Cu(NO₃)₂(aq) + 4KI(aq) → 2CuI(aq) + I₂(s) + 4KNO₃(aq)
molarity of KI = 0.209 M
mass of Cu(NO₃)₂ = 2.43 grams
number of moles of Cu(NO₃)₂ will be calculated as:
number of moles = [tex]\frac{mass}{atomic mass of 1 mole}[/tex]
atomic mass of Cu(NO₃)₂ = 187.56 grams/mole
putting the values in the equation,
number of moles= [tex]\frac{2.43}{187.56}[/tex]
= 0.0129 moles
2 moles of Cu(NO₃)₂ will react with 4 moles of KI
0.0129 moles will react with x moles of KI
[tex]\frac{4}{2}[/tex] = [tex]\frac{x}{0.0129}[/tex]
x = 0.0258
atomic mass of KI = 166.00 grams/mole
mass = 166.00 x 0.0258
= 4.28 grams or ml is the final volume of KI
so molarity = [tex]\frac{number of moles}{volume in litres}[/tex]
so molarity of KI is 0.0258 M, volume is 1 litre.
Using the formula
Minitial x Vinitial = M final Vfinal
V initial = [tex]\frac{M final Vfinal}{Minitial}[/tex]
= [tex]\frac{4.28 X 0.209}{0.0258}[/tex]
= 34.67 ml 0.034 liters of KI will be required.
3) Data given:
molarity of NaI = 0.724
number of moles of NaI =?
Volume in litres =?
formula used:
molarity = [tex]\frac{number of moles}{volume in liters}[/tex]
volume in litres = [tex]\frac{0.405}{0.724}[/tex]
= 0.55 liters is the volume
4) Data given:
Initial molarity = 0.3 M
initial volume = ?
final molarity = 0.04 M
final volume diluted by = 250 ml
formula used:
M initial X Vinitial = Mfinal X V final
putting the values in the equation:
Vinitial = [tex]\frac{0.04 X 250}{0.3}[/tex]
= 33.3 ml of 0.3 M solution will be required.
