First of all, we have
[tex]f(x-2)=f(1) \iff x-2=1 \iff x=3[/tex]
In fact, if we choose [tex]x=3[/tex], we have
[tex]f(3-2)=f(1)[/tex]
So, let's evaluate the given function at [tex]x=3[/tex]:
[tex]f(3 - 2)=f(1) = 3^3 + 3(3^2) - 3(3) +7 = 27+27-9+7=52[/tex]
Answer:
Step-by-step explanation:
f(x - 2) = f(1)
==> x -2 = 1
x = 2+1 = 3
f(x - 2) = f(3 - 2) = 3³ + 3*3² -3*3 + 7
= 27 + 27 - 9 + 7
= 54 - 2 = 52
