A site is compacted in the field, and the dry unit weight of the compacted soil (in the field) is determined to be 18 kN/m3. Determine the relative compaction if the maximum dry unit weight was measured to be 17 kN/m3. Express your answer as a percentage (but do not write the percentage sign in the answer box).

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onyebuchinnaji onyebuchinnaji · Answer 1 · 2020-04-17T07:41:54+02:00

Answer:

the relative compaction is 105.88 %

Explanation:

Given;

dry unit weight of field compaction, [tex]W_d_{(field)}[/tex] = 18 kN/m³

maximum dry unit weight measured, [tex]W_d_{(max)}[/tex] = 17 kN/m³

Relative compaction (RC) of the site is given as the ratio of dry unit weight of field compaction and maximum dry unit weight measured

Relative compaction (RC) = dry unit weight of field compaction / maximum dry unit weight measured

[tex]RC = \frac{W_d_{(field)}}{W_d_{(max)}}[/tex]

substitute the given values;

[tex]RC = \frac{18}{17} = 1.0588[/tex]

RC (%) = 105.88 %

Therefore, the relative compaction is 105.88 %