A student eats a dinner rated at 2000 (food) Calories. He wishes to do an equivalent amount of work in the gymnasium by lifting a 50 kg mass. How many times must he raise the mass to expend this amount of energy? Assume that he raises it a distance of 2 m each time and that he regains no energy when it is dropped to the floor. The acceleration due to gravity is 9.8 m/s2 and 1 food Calorie is 103 calories.

A Calorie is a measure of energy that calculated the amount of energy released from the foon it is broken down. The boy can lift the weight up to 879.49 times.

Calories:

It is a measure of energy that calculated the amount of energy released from the foon it is broken down.

Given food Calories,

Food Calories = 2000 x 103 calories

Food Calories = 206000 calories = 861904 J

The work done by boy can be calculated by the formula,

[tex]W = mgh[/tex]

Where,

[tex]m[/tex] - mass = 50 kg

[tex]g[/tex]- gravitational acceleration = 9.8 m/s²

[tex]h[/tex] - height = 2 m

Put the values in the formula,

[tex]W = 50\times 9.8\times 2\\\\W = 980\rm \ J[/tex]

So, boy can lift the weight,

[tex]x = \dfrac {861904 }{980 }\\\\x = 879.49[/tex]

Therefore, the boy can lift the weight up to 879.49 times.

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