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A shell of mass m and speed v explodes into two identical fragments. If the shell was moving horizontally (the positive x direction) with respect to Earth, and one of the fragments is subsequently moving vertically with speed v, find the velocity ' of the other fragment immediately following the explosion. (Use the following as necessary: v.)

Respuesta :

Answer:

The velocity of the other fragment immediately following the explosion is v .

Explanation:

Given :

Mass of original shell , m .

Velocity of shell , + v .

Now , the particle explodes into two half parts , i.e  [tex]\dfrac{m}{2}[/tex] .

Since , no eternal force is applied in the particle .

Therefore , its momentum will be conserved .

So , Final momentum = Initial momentum

[tex]mv=\dfrac{mv}{2}+\dfrac{mu}{2}\\\\u=v[/tex]

The velocity of the other fragment immediately following the explosion is v .

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