Answer:
Radius = 4.9m
Explanation:
The critical angle in optics refers to the angle of incidence, beyond which the total internal reflection of light occurs.
The formula for critical angle is;
θ_crit = sin^(-1)(n_r/n_i)
Where:
θ_crit = The critical angle.
n_r = refraction index.
n_i = incident index.
In this case n_i is refraction index of water which is given 1.33
While n_r is the refraction index of air which has a value of 1.
Thus,
θ_crit = sin^(-1)(1/1.33)
θ_crit = 48.75°
In critical angle statements, If the incident ray is precisely at the critical angle, the refracted ray becomes tangent to the boundary at the incidence point and propagates along the interface surface and there is no reflected ray. Thus;
Radius(r) = d.tan θ_crit
Radius = 4.3tan 48.75
Radius = 4.9m
The maximum radius of the circle will be "5.702 m". To understand the calculation, check below.
According to the question,
Water's index of refraction, μ = 1.33
Depth of pool = 4.3 m
We know the formula,
The angle of refraction,
→ n₁ × Sin₁ = n₂ × Sin₂
By substituting the values,
1 = 1.33 × Sin₂
Angle₂ = 48.75°
hence,
The max. radius will be:
= 5 × tan 48.75°
= 5.702 m
Thus the above response is correct.
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https://brainly.com/question/10729741
