Respuesta :
Answer:
The change on the second particle is [tex]2.93\times 10^{-16}\ C[/tex].
Explanation:
The period of revolution of the particle in the magnetic field is given by the formula as follows :
[tex]T=\dfrac{2\pi m}{Bq}[/tex]
It is given that the magnetic field is uniform. The mass of the second particle is the same as that of a proton but thecharge of this particle is different from that of a proton.
[tex]m_s=m_p[/tex]
If both particles take the same amount of time to go once around their respective circles. So,
[tex]T_e=T_s\\\\\dfrac{2\pi m_e}{Bq_e}=\dfrac{2\pi m_s}{Bq_s}\\\\\dfrac{m_e}{q_e}=\dfrac{m_p}{q_s}\\\\q_s=\dfrac{m_pq_e}{m_e}\\\\q_s=\dfrac{1.67\times 10^{-27}\times 1.6\times 10^{-19}}{9.11\times 10^{-31}}\\\\q_s=2.93\times 10^{-16}\ C[/tex]
So, the change on the second particle is [tex]2.93\times 10^{-16}\ C[/tex].
