Answer:
The correct answer is option A. "Culture B will have more colonies on the histidine-minus plate than culture A".
Explanation:
In this example, Culture B is a culture of E. coli that has been exposed to a mutagenic agent, therefore it has the potential of developing bacteria that by chance, is able to live in a medium lacking histidine. On the other hand, Culture A is the same E. coli culture but without the exposure to the mutagenic agent. The expected result is that Culture B will have more colonies on the histidine-minus plate than culture A, illustrating that a mutagenic agent can produce E. coli able to reproduce in a histidine-minus plate.