Answer:
Maximum acceleration will be [tex]195372m/sec^2[/tex]
Explanation:
It is given mass m =40 gram = 0.04 kg
Length of the wire l = 4 m
Frequency of transverse wave f = 860 Hz
Wavelength [tex]\lambda =0.5m[/tex]
Amplitude of the propagating wave [tex]A=6.7mm=0.0067m[/tex]
Angular frequency is equal to [tex]\omega =2\pi f=2\times 3.14\times 860=5400rad/sec[/tex]
Maximum acceleration is equal to [tex]a=\omega ^2A=5400^2\times 0.0067=195372m/sec^2[/tex]
So maximum acceleration will be [tex]195372m/sec^2[/tex]
